 Ch 5. Beam Deflections Multimedia Engineering Mechanics Integrationof Moment Integrationof Load Method ofSuperposition IndeterminateBeams
 Chapter 1. Stress/Strain 2. Torsion 3. Beam Shr/Moment 4. Beam Stresses 5. Beam Deflections 6. Beam-Advanced 7. Stress Analysis 8. Strain Analysis 9. Columns Appendix Basic Math Units Basic Equations Sections Material Properties Structural Shapes Beam Equations Search eBooks Dynamics Statics Mechanics Fluids Thermodynamics Math Author(s): Kurt Gramoll ©Kurt Gramoll MECHANICS - THEORY

In the previous sections, Integration of the Moment Equation, was shown how to determine the deflection if the moment equation is known. This section will extend the integration method so that with additional boundary conditions, the deflection can be found without first finding the moment equation. Differential Element from Beam

When constructing moment-shear diagrams, it was noticed that there is a relationship between the moment and shear (and between the shear and the loading). That relationship can be derived by applying the basic equations to a typical differential element from a loaded beam (shown at the left). First, summing the forces in the vertical direction gives

ΣFy = 0

V - (V + dV) - w(x) dx + 0.5 (dw) dx = 0

Both dw and dx are small, and when multiplied together gives an extremely small term which can be ignored. Assuming (dw)(dx) = 0, and simplifying gives, Next, summing moments about the right side (can be anywhere, but an edge is easier) and ignoring the 3rd order terms gives

ΣMright edge = 0

-M + (M + dM) - V dx + [w(x) dx][0.5 dx] = 0

Again, 2nd order terms such as dx2, are assumed extremely small and can be ignored. This gives Note, capital "V" is shear and not deflection, which is small "v".

Extending the Deflection Differential Equation w, M, V, Slope, and y Relationships
and Sign Conventions
(Note, w(x) is positice downward)

Recall, the basic deflection differential equation (Moment-Curvature Equation) was derived as This can be combined with dM/dx = V to give

 EIv´´´ = V(x) shear-deflection equation

This equation assumes E and I are constant along the length of the beam section. They can be combined with dV/dx = -w(x) to give

Thus, the deflection can be determined directly from the load function, but it does require four integrations and four boundary conditions. Where as using the moment-curvature equation, only two integrations and two boundary conditions are needed, but the moment equation must first be determined. Each Beam Section Requires its
Own Deflection Equation

The differential equation EIv´´´´ = -w(x) is not useful by itself but needs to be applied to a beam with specific boundary conditions. It is assumed that EI is constant and w(x) is a function of the beam length. The function, w(x), can be equal to 0. In fact, in most situations it does equal 0. For convenience, w(x) is considered positive when acting downward.

Integrating the equation four times gives, The integration constants, C1, C2, C3 and C4, are determined from the boundary conditions. For example, a pinned joint at either end of a beam requires the deflection, v, equal 0 and the moment, M, equal 0.. A fixed joint requires both the deflection, v, and slope, v´, equal 0, but moment and shear are unknown. Each beam section must have at least four boundary conditions. Details about boundary conditions are given below.

Each beam span must be integrated separately, just like when constructing a moment diagram. Thus, each new support or load will start a new beam section that must be integrated. Examples of beam sections are shown at the left.

Boundary Conditions

Determining the boundary conditions is usually the most difficult part of solving the deflection differential equation, especially when integrating four times. In particular, boundary conditions for multiple beam sections can be confusing.

The basic types of boundary conditions are shown below. Those conditions that require two sections are sometimes called continuity conditions instead of boundary conditions. For example, a point force on a beam causes the deflections to be split into two equations. However, the beam's deflection and slope will be continuous at the load location requiring v1 = v2 and v´1 = v´2. Also, the shear difference will equal the applied point load at that location, and the moment will be equal in both beam sections at that point, M1 = M2. These conditions are needed to solve for the additional integration constants. Typical Boundary Conditions (v, v´, V, M) for Beam Sections

Beam Deflection and Rotation Tool For complex beams with more than a couple loads, determining rotation and deflection is very difficult. Thus, most structural engineers will use a beam analysis tool to calculate the deflection and rotation curves. A simple one, based on finite element method, can be installed on any mobile device for free. .