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STATICS - CASE STUDY SOLUTION

    Position Vectors

Position Vectors
 

Coordinate systems can be attached to any point, but generally there is one or two points that are more convenient than others. For this problem, the coordiante system is placed at far right edge of the pipes. The position vector from the right edge of the pipe to joint B is

     rB = rBxi + rByj + rBzk

         = 45i + 0j + 15k

The position vector of point Q (location of applied force F) can be determined when the wrench is rotated at an angle of α as

     rQ = rQxi + rQyj + rQzk

         = 0i + 30 cosαj + (60 + 30 sinα)k

From vector addition, the position vector from joint B to point Q is

     rB + rBQ = rQ

or
     rBQ = rQ - rB

            = -45i + 30 cosαj + (45 + 30 sinα)k

     


Known Information

  Force Vector
 

The system of two forces can be replaced by an equivalent system consisting of a force FR and couple MR applied at point O. The force FR is found by summing the individual forces,

     F = Fxi + Fyj + Fzk

          = 0i - 80 sinαj + 80 cosαk

     
    Moment Vector


Moment Variation with Angle α
 

The moment of the force about joint B is given by

          MB = rBQ ×> F

The cross product in determinant form is

     

Expanding the equation gives

     MB = (rBQy Fz - rBQz Fy)i + (rBQz Fx - rBQx Fz)j
                        + (rBQx Fy - rBQy Fx)k

Substituting the appropriate values and simplifing to determine the moment at joint B gives

     MB = (2,400 + 3,600 sinα)i
                 + (3,600 cosα)j + (3,600 sinα)k

If the magnitude of MB is plotted as a function of the angle α, then the moment is a maximum at α = 90°, with a value of 6,997 N-cm or about 70 N-m. This is approximately 62% greater than the moment at α = 0°.

     
   
 
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