For the composite parts method, first break the wind load
into two parts: a uniform load of 40 lb/ft and a triangular load
of 0 lb/ft at the base and 80 lb/ft at the top of the building.
The force resultant of the uniform load and its location is
F_{1} = 40 (500) = 20,000 lb
y_{1} = 250 ft
The force resultant of the triangular load is
F_{2} = 0.5 (80) (500) = 20,000
lb
Its location is twothirds of the distance from the vertex to the peak
value
y_{2} = 2/3 (500) = 333.3 ft
Nest, combine these two forces into a single force F_{R} located
at the position y'.
F_{R} = ΣF
= F_{1} + F_{2} = 40,000 lb
Its location is given by
Substituting F_{1}, y_{1}, F_{2}, and y_{2}
and simplifying the equation gives
y' = 1.166 x 10^{7} / 40,000
= 291.7 ft
